Synthetic Route of 2163-00-0, These common heterocyclic compound, 2163-00-0, name is 1,6-Dichlorohexane, its traditional synthetic route has been very mature, but the traditional synthetic route has various shortcomings, such as complicated route, low yield, poor purity, etc, below Introduce a new synthetic route.
Examples 2 to 5; The procedure of Example 1 was repeated, except that the reaction of 1,6-dichlorohexane was carried out at a constant pH of 5, 6, 8 and 9. Before the start of the particular reaction, the weakly acidic mixture was adjusted to the pH of 5, 6, 8 and 9 with 2.5% sodium hydroxide solution (measurement with pH electrodes). Example 2 Example 3 Example 4 Example 5 pH value in 5.0 +/- 0.1 6.0 +/- 0.1 8.0 +/- 0.1 9.0 +/- 0.1 the reaction Residual 1,6-dichloro- <10 <10 <10 approx. 11 hexane content (ppm) Conversion of 1,6- >99.9 >99.9 >99.9 >99.9 dichlorohexane (%) In all examples (Examples 2 to 5), the resulting reaction mixture was clear and homogeneous. To determine the pure yield with respect to Examples 2 and 5, they were repeated once more. However, a GC analysis sample was not taken from the particular reaction mixture. The pure yield of the (di)sodium salt (di)hydrate of hexamethylene 1,6-bisthiosulphate was approx. 91.4%2) for the repetition of Example 2 and approx. 90.6%2) for the repetition of Example 5. 2) The pure yield for the synthesis according to Examples 2 and 5 was carried out again as in Example 1 by reacting the reaction solutions obtained in each case with aqueous NaBEC solution. In this procedure, the yield of 1,6-bis(N,N-dibenzylthiocarbamoyldithio)hexane was approx. 89.6% of theory with a content of 95% for the reaction according to Example 2 and approx. 89.7% of theory with a content of approx. 94% for that according to Example 5. Thus, the pure yield of the (di)sodium salt (di)hydrate of hexamethylene 1,6-bisthiosulphate in the inventive reaction of 1,6-dichlorohexane with sodium thiosulphate pentahydrate must have been approx. 91.4% for the reaction according to Example 2 (89.6%×0.95×1/0.931=91.4%) and approx. 90.6% for that according to Example 5 (89.7%×0.94×1/0.931=90.6%).
The synthetic route of 2163-00-0 has been constantly updated, and we look forward to future research findings.
Reference:
Patent; Buding, Hartmuth; US2005/240044; (2005); A1;,
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